I need to figure out a method to find and replace text within a text file. I have a file named, "myfile.txt" that has the following; testing=1 database=500 rules=30 I want the batch file to find database=500 and insert destination=300 under it. I want it to look like this; testing=1 database=500 destination=300 rules=30 I'll be using the NT platform for this. (NT,2000,XP,2003) Thanks MagnumVP

The following batch for NT systems fits your need For /F "tokens=1,2 delims==" %%A in (%1) Do ( Echo %%A=%%B>> %1.tmp If "%%A"=="database" ( Echo destination=300>> %1.tmp)) Move %1.tmp %1 I named it Atxt.bat and to run just type Atxt Pathname/FileName (e.g. Atxt Myfile.txt)

That gets me REALLY close. I appologize, I forgot one portion of the file. There is a [configuration] along with it, that seems to be messing with the batch. Here is what it was; [configuration] testing=1 database=500 rules=30 Here is what I get; Is there a way to get the "=" from after the [configuration]? [configuration]= testing=1 database=500 destination=300 rules=30 ALSO... Is there a way to assign variables so you don't have to pull it from %1? Example: SET Filename=Myfile.txt For /F "tokens=1,2 delims==" %%A in (%Filename%) Do ( Echo %%A=%%B>> %Filename%.tmp If "%%A"=="database" ( Echo destination=300>> %Filename%.tmp)) Move %Filename%.tmp %Filename% Thanks MagnumVP

Hi Magnum Doe's this help @echo off if exist newfile.txt del newfile.txt for /f "tokens=*" %%a in (myfile.txt) do call :AddText "%%a del myfile.txt rename newfile.txt myfile.txt exit /b :AddText %1 set Text=%~1% echo %Text% >> newfile.txt if "%Text%"=="database=500" echo desination=300 >> newfile.txt exit /b