Hi all, I have a string containing a complete path of a file in my BATCH file . I would like to extract only the path leaving the file name and previous directory. For example: k:\My test\bin\execute\test.bat. I just need to remove execute and test.bat and get the remaining of the string in my batch file. Please let me know the DOS command which i should use to achieve the same. Thanks in advance Sujie

Much depends on the version of DOS. ===================================== If at first you don't succeed, you're about average. M2

If your environment is a NT kernel based operating system, i.e. Windows NT/2K/XP, the batch below satisfies your need @Echo Off Set Var=K:\My test\bin\execute\test.bat For %%i in ("%Var%") Do Set CF=%%~dpi Set CF=%CF:~0,-1% :LOOP If "%CF:~-1,1%"=="\" GoTo :DONE Set CF=%CF:~0,-1% GoTo :LOOP :DONE Set CF=%CF:~0,-1% Echo %CF% Where Var holds the path to be parsed and CF the result. If however you are running a DOS based OS as Windows 9X/ME, I leave M2 the challenge.

Hey thanks for that..it does work but For %%i in ("%Var%") Do Set CF=%%~pi Set CF=%CF:~0,-1% After this line the drive letter is removed and CF is assigned to this? \My test\bin\execute\test.bat Any idea on this? Sujie

Yes, I edited the script I posted as I realized the minor bug, replace For %%i in ("%Var%") Do Set CF=%%~pi with For %%i in ("%Var%") Do Set CF=%%~dpi as you can see in the edited post #2 and you are done.

Thanks a lot..It was of great help.. and it worked fine.. I really appreciate your prompt response.:-) Sujie