Hey guys, this is quite an easy and obvious question, but I couldn't find the answer in my textbooks or online. Here's a problem: I have a class A, a class B derived from class A, and a class C derived from class B class A class B : public class A class C : public class B each of this classes has a method called print( ) , so it's like this: class A { print() {...} ; }; class B : public A { print() { A::print() ; ... ; } }; And class C : public B { print( ) { B::print() ; ... ; } } ; there's dynamic binding, so I have something like this A * a = new B() ; A * b = new C() ; a->print() ; b->print() ; Logically, print() in class A shoud be a virtual function, e.g. virtual print ( ) ; But what about print( ) in class B?? It's a base class for class C, afterall. Also, when I make print( ) in either class virtual method, my program doesn't compile, it spews thousands of linking errors on my screen. But if I leave virtual out, print() doesn't work as desired, only print() of class A is called for objects a and b. I'm tired of this. I can't ask anyone about it, because it's late at night, I can't find it on the Internet, because all examples portray classes derived from two different classes, but not from another derived class. My textbooks don't explain how to do it. I don't know how to link the damn thing so that it would work thank you for any help.

Hi. If you are talking about C++ then: 1) it is enough to declare a method as a virtual one only in the base class , in all derived classes the method will be virtual too. So if you declare A::print() as a virtual, them B::print() and C::print() will be virtual too. On the other hand it wont cause any damage if you declare all the print() methods as virtual; 2) It would be very usefull if you supply an example of the error message you get. 3) As far as I understand from your question, if you declare A::print() as virtual it should solve the problem.

try this code: class A { public: A(){} virtual print(){cout print(); b->print(); return 0; }