converting binary to decimal numbers that is all I need i think i did 2 much ---------------- #include #include #include //convert the string to number //udata is string //udatalen is length of string //base is numerical base eg. for decimal it is 10 // for hex it is 16 //largest base supported here is upto 36 int __fastcall StrToNum(const TCHAR *udata, int udatalen, int base) { long index; const TCHAR numdigits[] = TEXT("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"); long digitValue = 0; long RetVal = 0; TCHAR digits[sizeof(numdigits)+1]; TCHAR *dataVal; TCHAR data[512] ; //copy the data to our variable _tcscpy(data, udata); //convert it to upper case _tcsupr(data); ZeroMemory(digits, sizeof(digits)); //copy the number of digits supported by base in digits _tcsncpy(digits, numdigits, base); for(index = 0; index 36 ) return NULL; ZeroMemory(digits, sizeof(digits)); _tcsncpy(digits, numdigits, base); while(number) { digitValue = number % base; number = number base; RetVal[index++] = digits[digitValue]; } //since string we have got is in reversed format //eg 100 will be 001 so we have to reverse it //and put the value in our variable ZeroMemory(RetData, _tcslen(RetVal)+1); int i = 0; for(index = _tcslen(RetVal) - 1; index > -1; index--) { //start reversing RetData[i++] = RetVal[index]; } //return the result return RetData; } //our main function int _tmain(int argc, TCHAR* argv[], TCHAR* envp[]) { TCHAR Data[128]; ZeroMemory(Data, sizeof(Data)); //convert a number to string NumToStr(Data, 1123, 10); //now again convert string to number and see the result cout #include // For File I/O #include using namespace std; bool validate_line(string s); int bin_to_dec(string s); void pretty_print_line(string s); int main(void) { ifstream inFile; // Data file // Promts the user for a file name. string fileName; // File name string binary; cout > fileName; // Opens the File. inFile.open(fileName.c_str()); // Changes variable into a C string and opens the file. if (!inFile.good()) { cerr >= 1; // Divide multiplying factor by 2 each time } return n_retval; } void pretty_print_line(string s) { // Print the line without the leading spaces for (int i = 0; i s.size(); i++) if (s[i] != ' ') cout s[i]; } ---------------- Hopefully its one of these

I got it just didnt think hard enough #include #include #include void main() { clrscr(); int num,i,j,k,a1[30],l; char a2[30]; cout>num; for(i=0;num!=0;i++) { a1[i]=num%2; num=num/2; } k=i-1; for(j=0;ji;j++,k--) { a2[j]=a1[k]+48; } for(l=j;l=30;l++) { a2[l]=' '; } cout"\n\nThe Binary Number Is : "a2"\n"; getch(); }