I was trying to see if there is a method to count the number of files in a zip archive with out extracting it. I had a look at winzip's command line interface and there is a command for it but. wzunzip -vm test.zip WinZip(R) Command Line Support Add-On Version 3.1 (Build 8519) Copyright (c) 1991-2009 WinZip International LLC - All Rights Reserved Zip file: test.zip Length Method Size Ratio Date Time CRC-32 Attr Name ------------ ------ ------------ ----- ---- ---- -------- ---- ---- 0 Stored 0 0% 05/11/2009 09:31 00000000 --w- helloworld.txt 0 Stored 0 0% 05/11/2009 09:31 00000000 --w- helloworld2.txt ------------ ------------ --- --------- 0 0 0% 2 The number of files was hard for me to count I found UnZip 5.52 of 28 February 2005, by Info-ZIP Archive: test.zip Length Date Time Name -------- ---- ---- ---- 0 05/11/09 09:31 helloworld.txt 0 05/11/09 09:31 helloworld2.txt -------- ------- 0 2 files And that was a little better I was able to use unzip -l test|find "files" 0 2 files Do you think there is a better method or to try and use some thing stronger than a batch file also need to clean up the output some how 0 2 files need to be come 2 files The 0 is the zip size in the above example the files in the zip file are 0k so this will change so can't match it each time. Any ideas

I don't think piping it to find "files" will work. There may be a file in the zip archive called "files". This gets the second word from the last line, which is the number of files: setlocal for /f "tokens=2" %%a in ('unzip -l test') do set nfiles=%%a echo Number of files: %nfiles%

Good Points This is what I have come up with so far, One very handy part of my problem is the zip files will always hold XML files. But I need to populate %FIND RESULTS% with the results of find. @ECHO OFF set ERRORLEVEL= IF %1.==. GOTO NOZIP unzip -l %1| FIND /C /I "XML" > Nul if %ERRORLEVEL% EQU 0 ( GOTO ZiPRESULT ) else ( GOTO ZIPERROR ) :ZiPRESULT Echo There where %FIND RESULTS% XML files in %1 GOTO EXIT :ZIPERROR ECHO. ECHO I am sorry I had a error reading %1 Are you sure its a valid ZipFile GOTO EXIT :NOZIP ECHO. Echo No Zipfile Specified! ECHO. ECHO Example Useage: ECHO. Echo %0 Zipfile.zip GOTO EXIT :EXIT set ERRORLEVEL= ECho Exiting

I tried to use for FOR example to extract the result but can not see to get it to work @ECHO OFF setlocal set ERRORLEVEL= set MyVar= IF %1.==. GOTO NOZIP for /f "tokens=2" %%a in ('unzip -l %1 ˆ|FIND /C /I ".XML"') do set MyVar=%%a if %ERRORLEVEL% EQU 0 ( GOTO ZiPRESULT ) else ( GOTO ZIPERROR ) :ZiPRESULT Echo There where %MyVar% XML files in %1 GOTO EXIT :ZIPERROR ECHO. ECHO I am sorry I had a error reading %1 Are you sure its a valid ZipFile GOTO EXIT :NOZIP ECHO. Echo No Zipfile Specified! ECHO. ECHO Example Useage: ECHO. Echo %0 Zipfile.zip GOTO EXIT :EXIT set ERRORLEVEL= ECho Exiting Error | was unexpected at this time

is there actually a space between the escape ^ and the pipe character? if so, that might be your issue. should read like: unzip .. ^| find

The reason you get the error is that you are not using a caret (^) but some other obscure character instead (ˆ) - whatever that character is, it's not on my keyboard, so I don't know where you found it. Also, my FOR /F statement was designed to work only with exactly the command that I gave inside the brackets. If you're going to find to count the number of lines then don't tell it to use the second token, there's only one token in the output: for /f %%a in ('unzip -l %1 ^|FIND /C /I ".XML"') do set MyVar=%%a Also, you shouldn't need to handle ERRORLEVEL as an environment variable. For simplicity, remove the two SET ERRORLEVEL= statements and use this built-in statement instead: IF NOT ERRORLEVEL 1 ( GOTO ZiPRESULT ) else ( GOTO ZIPERROR ) Actually, I don't like GOTOs - you can just put your statements inside the IF/ELSE blocks instead of GOTOs.

Thanks for the replies guys I have fixed up the code with the ideas and cleaned it up, but have an issue with the errorlevel now not sure if I am getting the error level back from the "FOR command" When I pass a valid zip file I get a errorlevel 1 meaning invalid zip file/or problem running the find command No Zip file past (Working) zipcount No Zipfile Specified! Example Useage: zipcount Zipfile.zip Invalid Zip file (Working) zipcount HELLO unzip: cannot find either HELLO or HELLO.zip. I am sorry I had a error reading HELLO Are you sure its a valid ZipFile Valid Zipped XML files (not working) zipcount TEST.ZIP I am sorry I had a error reading TEST.ZIP Are you sure its a valid ZipFile Here is the code in a debug state where I echo out some of the values. zipcount TEST.ZIP Current error level is 1 I am sorry I had a error reading TEST.ZIP Are you sure its a valid ZipFile ZIP count is , Current error level is 1 @ECHO OFF setlocal set MyVar= IF %1.==. ( ECHO. Echo No Zipfile Specified! ECHO. ECHO Example Useage: ECHO. Echo %0 Zipfile.zip ECHO. GOTO :eof ) ELSE ( for /f %%a in ('unzip -l %1 ^|FIND /C /I ".XML"') do set MyVar=%%a echo Current error level is %ERRORLEVEL% IF NOT ERRORLEVEL 1 ( Echo There where %MyVar% XML files in %1 GOTO :eof ) else ( ECHO. ECHO I am sorry I had a error reading %1 Are you sure its a valid ZipFile ZIP count is %MyVar% , Current error level is %ERRORLEVEL% GOTO :eof ) ) Here is a copy of the zip file test files and unzip.exe as I am not sure if some times the syntax gets screwed when putting it here http://rapidshare.com/files/3027708... When I remove the Echo statement I see the MyVar set to the correct value of FIND, Looking at the find errorlevels I was expecting to get a errorlevel of 0 (as in the past code) 0 The search was completed successfully and at least one match was found. 1 The search was completed successfully, but no matches were found. 2 The search was not completed successfully. In this case, an error occurred, and FIND cannot report whether any matches were found.