I need to count the number of files in a directory. I used the following DOS Prompts-- Go to respective folder-- Set Count=0 ....... Dir * If not ErrorLevel 1 Set /A Count=%Count%+1 ....... Echo %Count% Files found. But this is not working. Can someone please help. Thanks in advance, Amrita

Hi Amrita, Try this: ::** dir /a-d | find /c ":" > NUMfiles.### set /p count=<NUMfiles.### ::** This assumes that your 'file time' layout contains a ":", like this: 03-03-2005 23:27 87 CHU2.BAT *** HTH M2

Thanks for the solution. I was looking for excel files in thwe directory, so I modified the code as follows: dir /a-d | find /c ".xls" > NUMfiles.### set /p count=<NUMfiles.### Echo %count% > count.txt This is working fine. Thanks a ton

Hi Amrita, Glad it's working. It always cheers me on when someone figures out how to alter the script to suit their needs. Gives you a sense of self-reliance. Best M2