Is there a function is C that converts a decimal number to a hex number and vice versa? I'm trying to access some data in memory with a known address. I determined the physical address in decimal. Actually, do I even need the conversion for accessing address(is there a parameter that define the unit that the number is in?) If you happen to know how to access data from address, that would be great too. Suppose I have a value 268 at the address of 0x00000059. How do I get that value from know the address of 0x00000059? Thanks!

Seems like these conversion functions are in demand... Here are some functions in C++, they can easily be converted to C... basically just changing the output syntax, etc. Using these functions, you should be able to generate the reverse to get the other conversion function... // Display a number in hex </br> void display_hex(int x) </br> { </br>   int i; </br>   int nonzero = 0; </br> </br>   cout << "Hex:     "; </br>   for(i = 7; i >= 0; i--) { </br>     nonzero += (x >> (i * 4)) & 0xF; </br>     if(nonzero) </br>       print_hex_digit((x >> (i * 4)) & 0xF); </br>   } </br> </br>   if(x == 0) </br>     print_hex_digit(0); </br> </br>   cout << "\n"; </br> } </br> </br> </br> // Display a hex digit </br> void print_hex_digit(int x) </br> { </br>   switch(x) { </br>   case 0: cout << "0"; break; </br>   case 1: cout << "1"; break; </br>   case 2: cout << "2"; break; </br>   case 3: cout << "3"; break; </br>   case 4: cout << "4"; break; </br>   case 5: cout << "5"; break; </br>   case 6: cout << "6"; break; </br>   case 7: cout << "7"; break; </br>   case 8: cout << "8"; break; </br>   case 9: cout << "9"; break; </br>   case 10: cout << "A"; break; </br>   case 11: cout << "B"; break; </br>   case 12: cout << "C"; break; </br>   case 13: cout << "D"; break; </br>   case 14: cout << "E"; break; </br>   case 15: cout << "F"; break; </br>   default: </br>     cout << "Error, print_hex_digit accepts 0-15 only\n"; </br>     exit(-1); </br>     break; </br>   } </br> }</br> IR

So much for using the code coverter... at any rate... take the br html code out and it should work for ya. IR

Thank you for your codes! I was able to C and it gave me the correct dec to hex conversion. Another question appears now. I need to store those hex numbers of an address and put them into a variable so I can access the information at that address. But when I put the string of numbers together into a variable called 'AddString', I do not only has the hex number, but also some beginning and terminal symbols like this 0X*0|*0|*0|*0|*0| *0|*2|*5|, where the hex number is only 0X00000025. What can I do to get rid of the * and | ? Here's my modified code for C. int main() { int number=37; int i; char* y; char AddString[15]="0X"; int nonzero = 0; puts("Hex: "); for(i = 7; i >= 0; i--) { nonzero += (number >> (i * 4)) & 0xF; { switch(((number >> (i * 4)) & 0xF)) { case 0: y[1]='0'; puts("0");break; case 1: y[1]= '1'; puts("1");break; case 2: y[1]= '2'; puts("2");break; case 3: y[1]= '3'; puts("3");break; case 4: y[1]= '4'; puts("4");break; case 5: y[1]= '5'; puts("5");break; case 6: y[1]= '6'; puts("6");break; case 7: y[1]= '7'; puts("7");break; case 8: y[1]= '8'; puts("8");break; case 9: y[1]= '9'; puts("9");break; case 10: y[1]='A'; puts("A");break; case 11: y[1]='B'; puts("B");break; case 12: y[1]='C'; puts("C");break; case 13: y[1]='D'; puts("D");break; case 14: y[1]='E'; puts("E");break; case 15: y[1]='F'; puts("F");break; default: puts("Error, print_hex_digit accepts 0-15 only\n"); } strcat(AddString, y); } } printf("Answer is: %s\n", AddString); return 0; } Thank you very much! Your help is being very appreciated!

sorry for delays on this, i actually lost this thread in the mycomputing.net feature. have you got it working yet? ir

Yep, now I got rid of that problem. However, when I try to access a memory location with the outputted address, it is not working. Is it because address is in Hex while the output of that program is in string? Is there any way to unwrap the string into a hex number? Thanks!