I was wondering how to have an array using strings. I've tried doing the following: char *arrayName[4]; *arrayName[0] = "purple"; *arrayname[1] = "red"; *arrayname[2] = "blue"; *arrayname[3] = "orange"; *arrayname[4] = "white"; However, when i try to print them out, by doing the following: printf("%c\n", *arrayname[0]); all i get is the first letter of the input color that i typed. For example if i make a loop to print out all the colors in the array using the printf method above, i would get: p r b o w How can i make it type out the entire name? Thanks, Brds85 brds85@gmail.com

Hi #include <stdio.h> void main() { rem [6]=String Length char *Name[4][6]; *Name[0] = "purple"; *Name[1] = "red"; *Name[2] = "blue"; *Name[3] = "orange"; *Name[4] = "white"; rem %s, %c = character printf("%s\n", *Name[4]); }

Hi: There's more than one way of initializing an array: #include <stdio.h> int main() { char *Name[] = { "purple", "red", "blue", "orange", "white" }; printf("%s\n", Name[0]); /* purple */ printf("%s\n", Name[4]); /* white */ }

1. Your array declaration should be *arrayname[5] since there are 5 elements 2. Use %s for strings in printf char *arrayname[5]; arrayname[0] = "purple"; arrayname[1] = "red"; arrayname[2] = "blue"; arrayname[3] = "orange"; arrayname[4] = "white"; for(int i=0;i<5;i++) printf("%s\n", arrayname[i]);