The following program (below my question) produces the results I want, but I am trying to create a for loop to replace all of the cout statements. What I have so far is: for (int i = 0; i <= len; i++) cout << str[i + 1]; This will prduce: "eed help with C++." Could someone clue me in on how to create the for loop? Should I be using a nested for loop? Any help would be appreciated. Program: #include<iostream> #include<cstring> using namespace std; void main () { const int arraySize = 20; char str[arraySize] = "Need help with C++."; int len = strlen (str); cout << "The sentence \"Need help with C++.\" has " << len << " characters." << endl << endl; cout << str << endl; cout << str + 1 << endl; cout << str + 2 << endl; cout << str + 3 << endl; cout << str + 4 << endl; cout << str + 5 << endl; cout << str + 6 << endl; cout << str + 7 << endl; cout << str + 8 << endl; cout << str + 9 << endl; cout << str + 10 << endl; cout << str + 11 << endl; cout << str + 12 << endl; cout << str + 13 << endl; cout << str + 14 << endl; cout << str + 15 << endl; cout << str + 16 << endl; cout << str + 17 << endl; cout << str + 18 << endl; } Results: The sentence "Need help with C++." has 19 characters. Need help with C++. eed help with C++. ed help with C++. d help with C++. help with C++. help with C++. elp with C++. lp with C++. p with C++. with C++. with C++. ith C++. th C++. h C++. C++. C++. ++. +. .

YOUR CODE: for (int i = 0; i <= len; i++) cout << str[i + 1]; Assumption: len is the number of characters in the string, not the position of the string ending NULL. Your loop is looping thru i values of 0 thru len. Thus your cout (with it's i+1) outputs str positions 1 thru len+1. There are two problems. You are skipping str[0], which you noted. Also, str[len+1] is a NULL character, which you don't normally output. So what you want is for the cout to output str positions 0 thru len (str[len] is the last character of the string. str[len+1] is the null). Changing the i+1 to i in the cout, will cause you to output 0 thru len. for (int i = 0; i <= len; i++) cout << str[i];

Thanks for the input. len is the length of the string. Using: for (int i = 0; i <= len; i++) cout << str[i]; outputs "Need help with C++" only once. I need to loop through the sentence and print it less one character each time. The result should look like the following: Need help with C++. eed help with C++. ed help with C++. ...

Don' put a semicolon on the end of the for loop and it should work

The generic form of your cout statements is: cout << str + i << endl; If you put this is a for loop that loops i from 0 to len, you should have it.

I forgot to add that I, obviously, didn't read your first post very carefully. Sorry about that.

I don't know that the for loop lends itself to be that useful here, but with a little trickery, you can try something like... #include <iostream> int main(void) { int i, j; char str[] = "Need help in C++."; i=j=0; for(; str[j] != '\0'; ) { if(str[i] == '\0') { std::cout << std::endl; j++; i=j; } else std::cout << str[i++]; } while(std::cin.get() != '\n'); return 0; } ... to force the desired effect. If the above works, then that grade is mine. :)