I am developing in vc++ 7 (.net) and am having a brain fart. I receie a byte buffer (bRecBuf) containing 00 64 90 The 90 referes to a success code so we can forget about the 3rd byte. The first and second byte are a multibyte hex that needs to be converted to an integer. so I have bRecBuf[0]; // 0x00 bRecBuf[1]; // 0x64 and I need to convert it to integer 100 I can do this in my head but cant programatically? any help is appreciated/ Thanks, Steve

int Result; Result = (int)bRecBuf[0] * 0x100 + (int)bRecBuf[1];

Thanks Jim but sorry I was not clear. The bytes in the buffer are hex code 0x00 and 0x64 and either can range from 0x00 to 0xFF. In this case 00 64 would translate to 100 and 00 01 would translate to 1. Thanks for the quick response.

> Thanks Jim but sorry I was not clear. Pretty sure that code will do what you want. > The bytes in the buffer are hex code 0x00 and 0x64 and either can range from 0x00 to 0xFF. In this case 00 64 would translate to 100 and 00 01 would translate to 1. Yes. It's in "Hi-Lo" order. You have to take the first byte and multiply it by 256 (0x100) and add the second byte. If it were in "Lo-Hi" order, you could just typecast the whole thing as a word. 02 10 would translate into 528, right? The (int) typecast will turn the byte into an integer. I expect your byte type is an unsigned char.