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Batch Sort List
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Original Message
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Name: stroke6463
Date: February 7, 2006 at 12:09:35 Pacific
Subject: Batch Sort ListOS: XP ProCPU/Ram: idk |
Comment: I need help with a batch. I have a text file that is sorted something like this. Add Apple Bear Cat Wow Xenon Quiet List Is there anyway to way to make it that when the next letter is out of alphabetical sequence it will remove the remainder of the text file. So "Quiet" and "List" would be deleted because they are not greater than X. I would like to know how to do it in a batch file, if it even is possible. Thanks.
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Response Number 1
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Name: IVO
Date: February 7, 2006 at 13:46:35 Pacific
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Reply: The following batch does that @Echo Off > %~pn1.out Set FOut=%~pn1.out Set PrevChar=~ For /f "tokens=* delims=" %%I in (%1) Do ( Call :SCREEN %%I) Set PrevChar= Set Char= Set FOut= GoTo :EOF :SCREEN Set Char=%1 Set Char=%Char:~0,1% If "%Char%" lss "%PrevChar%" GoTo :EOF Echo %*>> %FOut% Set PrevChar=%Char:~0,1% GoTo :EOF To run type at prompt Screen FileName (assuming the batch was stored as Screen.bat) and you get the filtered file in FileName.out. That works under Win NT/2K/XP only not 9X/ME and if you want to delete only the lines out of sequence and not the remainder of the file post again as the script needs to be adjusted.
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Response Number 2
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Name: IVO
Date: February 7, 2006 at 13:49:27 Pacific
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Reply: Please, note that the For /F statement fits just ONE line starting with For and ending with %%I) without CR/LF between Do and (Call.
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