I have a batch that checks daily for the month day and year. I have to change a file name to be -3 days on a monday to the previous fridays date. I have the months and years figured out but the problem is on a leap year it screws up my program. I just want the output to be 0 in 2008 confirming that it is a leap year. Here is an example: set Year=06 set /a Leap=%test:~1,1%%4 echo %Leap% The output is 6. When I manually run that from the command line step by step it works perfectly but when I run it from a batch it doesn't see the % operator. Any ideas? Thanks.

Hi Don't know what %Test% is, you need the full year to test for a leap year. Maybe this will work. set Year=06 set /a Leap=%test:~1,1%%%4 echo %Leap% The output is 6. or something like this @echo off set Year=2006 set /a LeapYr=%Year%%%4 if %LeapYr%==0 (echo Leap Year) else (Echo Not A Leap Year)

Like dtech10, I dunno what %test% is. But regardless, he's found the problem. A BAT 'strips' %, so you need one additional % within the BAT. If at first you don't succeed, you're about average. M2

Thanks guys. Sorry the test was supposed to be Year.