Batch file to delete specific words in txt

If you want to match the strings of two words wherever they are placed in the line (i.e. "Dog Mouse Bird 1112" or "Cow Dog Mouse 54444") assuming the words are separated by just one space the following does the job type file.txt | find /V "Dog Mouse" | find /V "Cow Fly" > file.new Otherwise post again explaining better your needs.

I beleive that does it!!! I could've swore I tried something similar to it but oh well. Thank you so much!

Actually, one more thing... :) Is there a way to ignore duplicate lines and just keep one line of the lines so: Dog Cat Horse 3456 Horse Dog Mouse 1234 Bird Cat Dog 4567 Dog Mouse Bird 1112 Dog Mouse Bird 1112 Dog Mouse Bird 1112 Horse Cow Fly 22234 Cow Dog Mouse 54444 Cow Fly Mouse 2323222 Cow Fly Mouse 2323222 Cow Fly Mouse 2323222 I want to filter any duplicates and have the following result: Dog Cat Horse 3456 Horse Dog Mouse 1234 Bird Cat Dog 4567 Dog Mouse Bird 1112 Horse Cow Fly 22234 Cow Dog Mouse 54444 Cow Fly Mouse 2323222 Thanks again!!!

If the duplicate lines are grouped in bursts the following applies... @echo off & setlocal EnableDelayedExpansion set /P row=< file.txt echo.%row%> file.new for /F "skip=1 delims=" %%j in (file.txt) do ( if not "%%j"=="!row!" echo.%%j>> file.new set row=%%j ) Otherwise the source file must be previously sorted, but the native order is lost.

Hmm.. it wont seem to work for me. Could you provide small amount of original and output text so I can see how the results worked out? Or can you maybe use my provided example text with this somehow?

Sorry, the script was untested and an extra space caused the bug. Please replace set row=%%j with (set row=%%j) and the batch should work fine.