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AWK in bash script

Comment:

I have a variable $len containing a number in inches and a variable $conv containing the inch to cm conversion factor. 1in = 2.54cm I am trying to get a command that will do: $len*$conv giving a CM value rounded to two decimal places. I have tried using: echo | awk '{s = $len*$conv; printf "%5.2f\n", s}' It does not like the variable useage. The other issue I have is I need to align the decimal on the 35th character on the screen: Assuming two decimal places: awk ' { printf("%37.2f\n", $1) } ' This command will work accept like the previous it does not accept variables, only files which will not work for me. Thanks for any help

Name: nails
Date: November 15, 2006 at 23:25:47 Pacific

Reply:

There are several ways to embed shell variables in awk scripts and to pass shell variables to awk scripts. Take a look at this link: http://www.tek-tips.com/faqs.cfm?fi...

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