I have a problem when executing pieces of code of this type:

main(){

char a,b;
a=getchar();
b=getchar();
}

The program waits for the first assignation and after the first character is stored,it exits without waiting
to receive the second character, ignoring the second instruction.
Can somebody tell me how to avoid this, so that both of the instructions can be executed?
I used gcc and Borland C++.

Thanks anticipated.

The problem is that 'a' is assigned the first character you enter, then 'b' is assigned the 'enter' key. You can avoid this by clearing STDIN after you get 'a'. You can do this by having a temporary buffer.

int main()
{
char a,b,buffer[32];
a = getchar();
gets(buffer);
b = getchar();

}

GCC will warn you about using the 'gets()' function, but in this case I think it is harmless.