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hi all
I have some questions
if the speed of the internet I use is 256 kbps , does it mean that I can transfer 256 kilo-bytes of data in one second?and which is faster :
1- to transfer a 10 Mbyte using 5 mbps DSL line , or
2-to transfer a 10 Mbit using 56.6 kbps dail-up connection?EADM

256 kilo bits/8=32 kilo bytes per send being the best you can get.
56.6/8=7.075 but you will never get that speed on dial up. 4 kilo bytes per second is the realistic speed you will get.
The 5meg DSL line should provide a good download rate of up to 640 kilo bytes per second. The 10 meg file will download in about 16 seconds versus 42.6 minutes on the 56k dial up line (at 4/sec)
Bryan

that is clearly somebody getting other people to answer some sort of school/exam questions....it stands out a mile !!

thanks brayan for replay
for the first question:I understand that you devide by 8 to convert from bit to byte that means we can say that it can transfer 256 kilo-bit per secondthe second question I didnt really know from where you get the 640 KB .. since the file size is 10 Mbyte = 10/8=1.25 Mbit we divide it by the rate which is 5 Mbps to get 0.25 seconds , when we use the dail-up the file size is 10 Mbit so we dont need to divide by 8 with a speed of 56.6 kbps we get 10/56.6=0.17 which is faster than the dsl line .. did you say that the DSL is faster because the meduim used to transfer is difrent or because dail-up is not utilizing the well?
friutgoo
I've just finished final exams yesterday :)EADM

Wow....check your math FADM...you're way off in your calculations.
Your question quoted DSL at 5 Mbps....that's 5 Megabits per second that's the equivalent of 5000 bits per second. Compare that to your dialup rate of 56.6 kilobits per second.
I can tell you from experience that a 10 Mb file on dialup takes 45 to 60 min's under optimal conditions. The DSL, being about 100 times faster will (again, optimally) take less than 1 minute.
You didn't pass that exam, did you.

you didn't get the point I am talking about..
In case of DSL I want to transfer a file with size=10MByte
While in case of using Dauil-up the file size = 10Mbits
we didnt get something like this in the exam .. I didnt get my grades yet but I will pass with grade 'A'EADM

Even though this question was not on your exam, if you don't know the answer, how can you say you'll get an A? The answer to this question is basic arithmetic.
http://www.homenethelp.com/web/explain/about-network-speeds.asp

Thanks for that link it is really useful
but I have another question:Why most of ppl here are very polite ?!?!?
EADM

Why most of ppl here are very polite ?!?!?
I guess we're more matured, confident and fully seasoned from reading and answering all kind of posts whether or not it has anything to do with the theme of each CN Forums.
i_XpUser

Easy -
10 MB - 256 Kbps
10 Mb - 56.6 Kbps8 bits in a byte, so you would think to use 8 X 10MB to get bits, then divide bits by xfer rate per second.
80 Mb / 256 = 312500 seconds
10 Mb / 56.6 = 176678.45 seconds
312500 / 176678.45 = 1.77But you can do the same thing by 8 X 56.6 , which comes up to 452.8 which is more than 256.
452.8 / 256 = 1.77WILL POST FOR FOOD.

"Your question quoted DSL at 5 Mbps....that's 5 Megabits per second that's the equivalent of 5000 bits per second."
Plenty of new math in this thread.
If at first you don't succeed, you're about average.M2

(10 MByte x 1000000 Byte/MByte x 8 bits/Byte)
over
(256 Kbps x 1024 bits/K)
= 305.2 seconds(10 Mbits x 1000000 bits/M)
over
(56.6 Kbps x 1024 bits/K)
= 172.5 secondsTherefore 10 Mbit file over the 56.6 Kbps connection will finish first. This is reasonable as the 10 Mbyte file is about 8 times bigger and being transfer over a connection that is only 4 times faster.
Neither example takes overhead into account. Adding the overhead for 1 stop bit per 8 data bits makes the times 340 and 194 seconds respectively.
Numbers also change if you call a Kbyte 1000 instead of 1024.

Oops, like the teacher said, read the question,
Part 1
No, 256 kpbs means 256 x 1024 _bits_ per second.
Part 2,
(10 MBytes x 1000000 bytes/M x 8 bits/byte)
over
(5 Mbps x 1000000 bits/M)
= 16 seconds(10 Mbits x 1000000 bits/M)
over
(56.6 Kbps x 1024 bits/K)
= 173 secondsTherefore when you read the question correctly the 10 MByte file over the 5 Mbps connection will complete first (not including overhead).

Wondered when the overhead would show up.
A file transfered is MUCH larger in transfer size than the original size of the file even on ftp.

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