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which is faster?

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Name: EADM
Date: January 6, 2006 at 05:30:52 Pacific
OS: xp
CPU/Ram: 256
Comment:

hi all

I have some questions
if the speed of the internet I use is 256 kbps , does it mean that I can transfer 256 kilo-bytes of data in one second?

and which is faster :
1- to transfer a 10 Mbyte using 5 mbps DSL line , or
2-to transfer a 10 Mbit using 56.6 kbps dail-up connection?

EADM



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Response Number 1
Name: Bryco
Date: January 6, 2006 at 06:03:52 Pacific
Reply:

256 kilo bits/8=32 kilo bytes per send being the best you can get.

56.6/8=7.075 but you will never get that speed on dial up. 4 kilo bytes per second is the realistic speed you will get.

The 5meg DSL line should provide a good download rate of up to 640 kilo bytes per second. The 10 meg file will download in about 16 seconds versus 42.6 minutes on the 56k dial up line (at 4/sec)

Bryan


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Response Number 2
Name: fruitygoo
Date: January 6, 2006 at 06:16:00 Pacific
Reply:

that is clearly somebody getting other people to answer some sort of school/exam questions....it stands out a mile !!


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Response Number 3
Name: EADM
Date: January 6, 2006 at 07:45:44 Pacific
Reply:

thanks brayan for replay
for the first question:I understand that you devide by 8 to convert from bit to byte that means we can say that it can transfer 256 kilo-bit per second

the second question I didnt really know from where you get the 640 KB .. since the file size is 10 Mbyte = 10/8=1.25 Mbit we divide it by the rate which is 5 Mbps to get 0.25 seconds , when we use the dail-up the file size is 10 Mbit so we dont need to divide by 8 with a speed of 56.6 kbps we get 10/56.6=0.17 which is faster than the dsl line .. did you say that the DSL is faster because the meduim used to transfer is difrent or because dail-up is not utilizing the well?


friutgoo
I've just finished final exams yesterday :)

EADM


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Response Number 4
Name: Curt R
Date: January 6, 2006 at 10:30:07 Pacific
Reply:

Wow....check your math FADM...you're way off in your calculations.

Your question quoted DSL at 5 Mbps....that's 5 Megabits per second that's the equivalent of 5000 bits per second. Compare that to your dialup rate of 56.6 kilobits per second.

I can tell you from experience that a 10 Mb file on dialup takes 45 to 60 min's under optimal conditions. The DSL, being about 100 times faster will (again, optimally) take less than 1 minute.

You didn't pass that exam, did you.



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Response Number 5
Name: EADM
Date: January 6, 2006 at 11:03:29 Pacific
Reply:

you didn't get the point I am talking about..
In case of DSL I want to transfer a file with size=10MByte
While in case of using Dauil-up the file size = 10Mbits


we didnt get something like this in the exam .. I didnt get my grades yet but I will pass with grade 'A'

EADM


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Response Number 6
Name: FishMonger
Date: January 6, 2006 at 11:35:27 Pacific
Reply:

Even though this question was not on your exam, if you don't know the answer, how can you say you'll get an A? The answer to this question is basic arithmetic.

http://www.homenethelp.com/web/explain/about-network-speeds.asp


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Response Number 7
Name: EADM
Date: January 6, 2006 at 14:31:19 Pacific
Reply:

Thanks for that link it is really useful

but I have another question:Why most of ppl here are very polite ?!?!?

EADM


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Response Number 8
Name: XpUser
Date: January 6, 2006 at 14:36:58 Pacific
Reply:

Why most of ppl here are very polite ?!?!?

I guess we're more matured, confident and fully seasoned from reading and answering all kind of posts whether or not it has anything to do with the theme of each CN Forums.

i_XpUser


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Response Number 9
Name: Zenith
Date: January 6, 2006 at 14:40:14 Pacific
Reply:

Easy -

10 MB - 256 Kbps
10 Mb - 56.6 Kbps

8 bits in a byte, so you would think to use 8 X 10MB to get bits, then divide bits by xfer rate per second.
80 Mb / 256 = 312500 seconds
10 Mb / 56.6 = 176678.45 seconds
312500 / 176678.45 = 1.77

But you can do the same thing by 8 X 56.6 , which comes up to 452.8 which is more than 256.
452.8 / 256 = 1.77

WILL POST FOR FOOD.



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Response Number 10
Name: Mechanix2Go
Date: January 7, 2006 at 19:11:10 Pacific
Reply:

"Your question quoted DSL at 5 Mbps....that's 5 Megabits per second that's the equivalent of 5000 bits per second."

Plenty of new math in this thread.


If at first you don't succeed, you're about average.

M2


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Response Number 11
Name: DaveB (by DaveBruce)
Date: January 7, 2006 at 19:50:04 Pacific
Reply:

(10 MByte x 1000000 Byte/MByte x 8 bits/Byte)
over
(256 Kbps x 1024 bits/K)
= 305.2 seconds

(10 Mbits x 1000000 bits/M)
over
(56.6 Kbps x 1024 bits/K)
= 172.5 seconds

Therefore 10 Mbit file over the 56.6 Kbps connection will finish first. This is reasonable as the 10 Mbyte file is about 8 times bigger and being transfer over a connection that is only 4 times faster.

Neither example takes overhead into account. Adding the overhead for 1 stop bit per 8 data bits makes the times 340 and 194 seconds respectively.

Numbers also change if you call a Kbyte 1000 instead of 1024.


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Response Number 12
Name: DaveB (by DaveBruce)
Date: January 7, 2006 at 20:03:27 Pacific
Reply:

Oops, like the teacher said, read the question,

Part 1

No, 256 kpbs means 256 x 1024 _bits_ per second.

Part 2,

(10 MBytes x 1000000 bytes/M x 8 bits/byte)
over
(5 Mbps x 1000000 bits/M)
= 16 seconds

(10 Mbits x 1000000 bits/M)
over
(56.6 Kbps x 1024 bits/K)
= 173 seconds

Therefore when you read the question correctly the 10 MByte file over the 5 Mbps connection will complete first (not including overhead).


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Response Number 13
Name: jefro
Date: January 14, 2006 at 15:32:18 Pacific
Reply:

Wondered when the overhead would show up.

A file transfered is MUCH larger in transfer size than the original size of the file even on ftp.


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Response Number 14
Name: Woof
Date: February 14, 2006 at 11:20:06 Pacific
Reply:

My brain hurts!!!

:P

Woof

Always proof-read carefully to see if you any words out.


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