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Subnetting pt2!

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Name: nnishp
Date: May 22, 2005 at 07:11:06 Pacific
OS: XP Pro SP2
CPU/Ram: P4 2.4 / 1 GB DDR
Comment:

My next problem question is:

You have the network address of 196.119.203.0 with a /27 mask. How many usable hosts can you create? I know the answer is 180 but i am a bit confused as to how to get that answer.

D thanks for your help previously, if you can do it again then i'll be very grateful



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Response Number 1
Name: Curt R
Date: May 22, 2005 at 07:27:17 Pacific
Reply:

A IP address breaks down into two parts. Network and host bits. The network portion denotes the number of networks, the Host, the number of hosts available on each network. With network being the bits on the left and host the bits on the right.

As to your question. I think you're crossing up your CIDR notation with the subnet mask. Are you trying to find out the number of networks/hosts on the following:
192.119.203.0/27

Here's a link to a good online subnet calculator. Perhaps it will help you get a better understanding of subnetting:

http://www.subnetmask.info/


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Response Number 2
Name: computingMonk
Date: May 22, 2005 at 08:07:29 Pacific
Reply:

perhaps he just mistyped.

There are 10 types of people in the world, those who know binary, and those who don't.


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Response Number 3
Name: nnishp
Date: May 22, 2005 at 09:45:39 Pacific
Reply:

i just copied and pasted the question, i have tried the site you mentioned but i need to know how to calculate it without the aid of a subnet calculator. Thanks


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Response Number 4
Name: dknowledge
Date: May 22, 2005 at 12:59:24 Pacific
Reply:

Kind of a two step process, you have to determine the number of host per network, and the number of networks. So:

First you translate the /27 which is accordingly 27 ones.


11111111.11111111.11111111.11100000

The ones represent the networks, and the zeros represent the hosts.

Since you have 5 zeros then you use 2*n (where n is 5), for a total of 32 host, BUT you have to subtract 2 because the first host is the network address, and the last host is the broadcast address so you get 30 host per network.

Since you have 3 ones then you use 2*n (where n is 3) for the total number of usable networks, which is 8, BUT again you have to subtract 2 because the first and last are not usable again, for a total of 6.

6 networks, with 30 host each -> 30 * 6 = 180.

Just stick to the formula 2*n - 2, for both networks and host and you should be fine.

And Curt R was "splitting hairs" ...anyone knowing networking would know what you meant by /27.

D


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Response Number 5
Name: surcha
Date: May 27, 2005 at 07:24:01 Pacific
Reply:

Can anyone please provide a website link which explains the /27.

Thx


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