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SUBNETTING IPv4 CLASS "B" ADDRESS
(hint:2^n-2 subnets for n bits taken from host addresses; 2^m -2 hosts for m available bits -(m+n) = total number of bits not part of network address)1) You are at a large company and decided to implement a private address space for your internal network. You decide to use the class B address (172.17.0.0/16) - this means your network address is 172.17.0.0. The number of bits in the subnet mask is 16 and your default subnet mask is 255.255.0.0
a) How many hosts are on this network?
b) why would you not want this many hosts on your network?
c) you decide to have 50 networks. How many bits do you need to take from the host part of the address to create 50 networks?
d) What is the new Subnet mask?
e) How many usable hosts are on each subnet?
f) List the first three usable subnets
g) List the last three usable subnets.
h) List the first three usable host addresses in the third subnet.
i) List the broadcast address in the third subnet.IPv4 CLASS "C" ADDRESS
2) Assume that your company has purchased the 214.56.42.0 class C network block. This is a range of public addresses which you will assign to the internet accessible devices such as your NATs and routers
a) you decide to have 14 hosts on each subnet - how many bits will you need
b) this leaves ___________binary digits are left for the subnet address.
c) This will give you ___________ subnets.
d) Specify the subnet mask in a dotted decimal notation.
e) Specify the subnets in dotted Decimal notation and in binary format for the last octet.
f) List the range of usable host addresses on the second subnet
g) what is the broadcast address for the second subnet.
If it is just for fun I don't see the fun in asking a question and getting someone else to answer it. I would have thought the fun would be in asking the question and working it out for yourself.
Stuart
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And you thought the helpers here were no brainers :-) Sorry you flunked the trick attempt with us.
i_Xp/Vista/W7User
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So you think, we need extra exercises like yours?
Take a look at this forum and think about it.
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jweston
Who devised this question? The questions are too well written and too pertinent not to be written by someone who already knows the answers. I gave up answering questions from somebody that already knows the answers a long time ago.
If you do know the answer, why are you asking the question, you think we need the exercise.
If you don't know the answers, then who is asking the question? A tutor, a teacher!
So give us some indication that you fall into the former group and not the latter.
Stuart
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 DLSW redundancy problem
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