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I have a small network set up at home w/ two computers connected to a router. I have a cable modem connection to the Internet, which the router goes through the cable modem. On one computer I can connect to the Internet and it had an Ethernet card put in there by the cable guy. It is on the 2nd computer in another room in which I'm having a problem though. I can't get that computer to connect to the Internet. The browser always returns the can't find server message. In that computer I have an Ethernet card installed as well with the driver software installed properly. However, it is a different Ethernet card, one that came with a prior home network kit I had. As far as I know I have everything set up and connected correctly for both computers to communicate through the router and modem to get to the Net. Is there a possible issue with there needing to be the same exact Ethernet cards used in all computers on the same network? They're both 10/100 mb ethernet cards, but by different vendors. I didn't think that would be relevant. Nothing I've tried has worked. Does anyone know why I can't connect to the Internet from the other computer? Please help.

go to the second computer and find out its ip address:
start>run>cmd [enter]
type 'ipoconfig' without quotes for newer Windows operating systems, and 'winipcfg' for win 9x systems.if it is 0.0.0.0 or 169.254.x.x then go to your tcp/ip properties located under network connections and set it to obtain ip address automatically. you will also want to select obtain dns info automatically if the option is available. if you know how to release and renew your ip address do that if not reboot.
As long as the card is a 10/100 auto sensing card you should not have any problems.
If your card has a 192.168.x.x ip address then see if you can ping the other computer. If it is similar to my setup at home the modem hooks into the switch/router and then the router hands out DHCP addresses to the computers connected to it. They must be set to use DHCP though by selecting obtain ip address automatically.

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