HI Gurus I need Unix Shell Script for Telnet , Can any one help me if he has already. I saw some old posts here for same problem , but not solutions in it. Looking fwd for help soon . Thanks for all BRs zia

Use EXPECT. http://expect.nist.gov #!/pathtoexpect #globals exp_internal 0 set timeout 125 log_user 0 set prompt "myname@hostname" proc get_str {str} { puts -nonewline $str stdout flush stdout stty -echo set rr [gets stdin] stty echo return $rr } catch { spawn -noecho telnet [lindex $argv 0] set id $spawn_id expect { -re ".*ogi.*" { set l [get_str "Need login: "] send "$l\r" exp_continue } -re ".*asswor.*" { set l [get_str "Need Password: "] send "$l\r" exp_continue } -re "$prompt" { send_user "Logged in\n\n" interact {} } eof { send_user "Caught premature eof." close ; wait } timeout { send_user "Timed out on [lindex $argv 0]" } } }

Hi Gurus, Is there any version of such code which save everything to a file after a telnet is send?. I'd like to send "telnet " and then send a command to a remote console which does not request for user and password. After it i'd like to see the answer into a file. Thanks for coops. Brgds, David

Hi, I'd like to end a telnet process but without waiting for a ^Z as described below according to an "expect" example. If I remote ^Z, the file is empty. Is there any other way to stop the process without waiting for the user action. The unix action is $expect telnet.sh > file.dat The telnet.sh code is: spawn -ignore HUP telnet $IP $PORT;# start telnet interact \032 return ;# interact until ^Z if {[fork]} exit ;# disconnect from terminal disconnect set log [open logfile w] ;# open logfile expect -re .+ { ;# and record everything to it puts -nonewline $log $expect_out(buffer) exp_continue } Thanks for coops.