OK!!! I found. It can be done this way: FILE *fp; char so[4096]; fp=popen("TZ=\"Europe/Moscow\" date","r"); if(fp!=NULL) { fgets(so,80,fp); pclose(fp); } Thank you.

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Fair enough but it is just as easy to use the library functions: time_t now; struct tm *now_tm; putenv("TZ=Europe/Moscow"); now=time(NULL); now_tm=localtime(&now)); Now you've got access to the members of now_tm which have all been set to Moscow local values and also the extern tzname string which localtime() sets to the timezone name (%Z in the example below). #include <stdio.h> #include <string.h> #include <time.h> #include <stdlib.h> #define SIZE 256 int main (int argc, char *argv[]) { time_t now; struct tm *now_tm; char tzsave[64]="TZ"; char buff[SIZE]; if (getenv("TZ") != (char *) NULL) { strcat(tzsave,"="); strcat(tzsave,getenv("TZ")); } if (argv[1] != (char *) NULL) setenv("TZ",argv[1],1); now=time(NULL); now_tm=localtime(&now); strftime(buff,SIZE,"%A, %B %d %Y: %r %Z\n",now_tm); fputs(buff,stdout); putenv(tzsave); }

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Hi , I am using setenv("TZ", zone, 1); ,to get the a time of that zone .But i am facing memory leak ,even if i use unsetenv("TZ"). I am going in a loop and giving diffenrent time zones . How to avoid this ? Thanks Kannan

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Without seeing the code, I couldn't say exactly - it depends on how you are dealing with the strings. A trivial modification of the previous programme to do something similar to what you are describing would be: #include <stdio.h> #include <string.h> #include <time.h> #include <stdlib.h> #define SIZE 256 int main (int argc, char *argv[]) { time_t now; struct tm *now_tm; char tzsave[64]="TZ"; char buff[SIZE]; int i=1; if (argv[1] == (char *) NULL) { fprintf(stderr,"Usage: %s timezone1 [timezone2] ...\n",argv[0]); return EXIT_FAILURE; } if (getenv("TZ") != (char *) NULL) { strcat(tzsave,"="); strcat(tzsave,getenv("TZ")); } now=time(NULL); while (argv[i] != (char *) NULL) { setenv("TZ",argv[i],1); now_tm=localtime(&now); strftime(buff,SIZE,"%a. %B %d %Y, %r %Z\t",now_tm); strcat(buff," ["); strcat(buff,argv[i]); strcat(buff,"]\n"); fputs(buff,stdout); i++; } putenv(tzsave); } Of course the string array argv[] is automatically large enough to hold all the timezone strings (up to the maximum length of the command line) but if you are getting them from elsewhere you must malloc the necessary space yourself. BTW, I don't usually look at the messages that aren't on the first page and I suspect most people don't, so if a thread is that old it's probably better to start a new one.

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Hi, Thanx for the answer ... Here is the code what i am using ... Originally TimeStamp(); is the code i am using ...The function is called just as in main. This is a similar scenario. #include<string.h> #include<time.h> #include<stdlib.h> #include<stdio.h> main(int argc, char *argv[]) { unsigned char getTimeStamp[6] ; char zone[80], i = 0; while (argv[i] != (char *) NULL) { strcpy(zone, argv[i]); TimeStamp(getTimeStamp, zone); i++ ; } } int TimeStamp(unsigned char *getTimeStamp , char *zone) { time_t now; struct tm tnow; int curYear ; setenv("TZ" ,zone ,1); time(&now); tnow = *localtime(&now); curYear = tnow.tm_year + 1900 ; getTimeStamp[0] = curYear - 2000 ; getTimeStamp[1] = tnow.tm_mon + 1 ; getTimeStamp[2] = tnow.tm_mday ; getTimeStamp[3] = tnow.tm_hour ; getTimeStamp[4] = tnow.tm_min ; getTimeStamp[5] = tnow.tm_sec ; unsetenv("TZ"); return 0; } Thanks Kannan

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I can't see anything very wrong with it and it compiles and runs without error on my system.

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