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Shell scripting help
Name: Hiran Date: April 12, 2003 at 14:22:25 Pacific OS: Debian CPU/Ram: AMD 900/128MB
Comment:
I'm trying to write a script to batch convert wavs to mp3s. So far I have this:
for file in `ls [Directory]` ; do lame -b 320 -q 0 $file.wav $file.mp3 done
But the problem seems to be that even though ls lists the full file name (w/ spaces and all), each name is being broken up with space as the token (I tried an echo $file to confirm this). I was thinking I could concatenate $file with some temp variable and then when $file has a ".wav" in it, do the conversion and then reinitialize the variable. If so, how do I check the last four characters of $file? Or is there a better way to do this? Thanks.
Name: David Perry Date: April 12, 2003 at 20:58:25 Pacific
Reply:
The rename command would be a big help to you if you want to remove spaces from file names.
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Response Number 2
Name: danco Date: April 13, 2003 at 11:04:40 Pacific
Reply:
Hiran, I'm trying to do exactly this same thing -- did you find a simple solution yet? I found autolame and some other tools at http://www.mp3-converter.com/linux/ but I was hoping to find a simple script just like you have above. If you find a simple scripting solution, please let me know.
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Response Number 3
Name: ramadog Date: April 13, 2003 at 18:54:39 Pacific
Reply:
Something like this should work
#!/bin/bash
for i in *.wav do NAME=`basename "$i" .wav` lame "$NAME".wav "$NAME".mp3 done
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Response Number 4
Name: danco Date: April 13, 2003 at 20:50:38 Pacific
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