hey guys...having some issue using vmplayer for a unix class, and i really suck at scripts...can someone help me figure this out. #!/bin/Project 5 2 # 22 November 2008 # Created by Charles Clay # This program adds five numbers entered on the command line together # Check to see if five numbers were entered if [[ $# -eq 5 ]] then # Display the numbers entered echo "The first number is: "$1 echo "The second number is: "$2 echo "The third number is: "$3 echo "The fourth number is: "$4 echo "The fifth number is: "$5 # Add the numbers together and divide by 5 to display average ((myaver=$1+$2+$3+$4+$5/5)) echo "Your average is: "$myaver if [[ $myaver -ge 0 && $myaver -le 68 =$F ]] then echo "Your average is a F" fi echo "Your average is: "$myaver if [[ $myaver -ge 68 && $myaver -le 73 ]] then echo "Your average is a D" fi echo "Your average is: "$myaver if [[ $myaver -ge 73 && $myaver -le 79 ]] then echo "Your average is a C" fi echo "Your average is: "$myaver if [[ $myaver -ge 79 && $myaver -le 91 ]] then echo "Your average is a B" fi echo "Your average is: "$myaver if [[ $myaver -ge 91 && $myaver -le 101 ]] then echo "Your average is an A" fi else echo "Please enter only five numbers" echo "Usage: $0 value1 value2 value3 value4 value5 /5" exit 0 fi # End script It calculates the wrong average and says that it can not find

First, you are performing the aritmetic incorrectly; it should be: myaver=$(( ($1+$2+$3+$4+$5)/5)) Keep in mind that the bash shell only does integer arithmetic. In our example, any result not divisible by 5 will be truncated. If you need more accuracy, use a tool like bc or awk to do the arithmetic. Let me know if you want an example.

mista, you should at least add some brackets to your calculation: ((myaver=($1+$2+$3+$4+$5)/5)) cheers Wollie