|My problem is that all forums (this one included) contain threads that contradict each other and almost all contain no indication as to the basis of why the opinion expressed is correct.|
Nor do almost all of these threads contain information relevant to the significantly different exercise of removing a component, or touching a component already inside a PC, versus taking a new component out of its packet (or from another PC) and then installing it in the PC in question.
Granted, if you are going to remove a component from inside a PC (not attached to earth), the component, yourself and the chassis will all be at the same potential if you are touching the chassis with the other hand or attached to the chassis with a wrist strap. No problem; now remove any component to your heart's content.
But what if you are about to insert a new component?
It will have come to you in an anti-static bag and no doubt was placed inside that bag in an enviroment at earth potential at it's point of manufacture.
So, if you are at chassis potential of a PC that perhaps has been disconnected from its power cable and perhaps moved from one place to another since then, or has accumlated a charge courtesy of you touching it, are you and the chassis necessarily now at the same potential as the "static free" component you are about to remove from it's bag?
What about if you have removed a component from another PC and had it lying somewhere on the bench top and now you go to pick it up?
And lastly, just because a component was put in a bag at earth potential in say Taiwan, is it necessary at the same earth potential as a grounded PC on theother side of the world that you are now working with?
So what's the answer to working correctly? Wrist strap connected to chassis, with chassis plugged in to a power point that is not turned on? Or Chassis unplugged?
Anf how do we ensure that a new component has been brought to the same potential as it's new PC home, without the very act of bringing it to the same potential causing it to malfunction?