Is it possible to write a batch file to delete the first 4 lines of a particular text file. It has to be windows based Thanks

Yep, that's possible. The following batch script will do the job. The sintax is: filename.bat textfile Actually, the assembler code makes all the job in this batch script. ===== BATCH SCRIPT BEGIN ===== @echo off if "%1"=="GoTo:" goto %2 if "%1"=="" goto eof if not exist %1 goto eof %COMSPEC% /c %0 GoTo: dbgsrc |DEBUG %1 > nul goto eof :dbgsrc echo e00 83 F9 0 74 1A BE 0 1 3D 4 0 74 9 BF FF 0 echo e10 80 3C A 75 1 40 A4 E2 EF 89 F9 81 E9 0 1 echo g=0 1F echo w100 echo q :eof ===== BATCH SCRIPT END ===== Watch out for line wrapping! I haven't tested it on a NT system, but I don't see any reason why it shouldn't work. -- Leonardo Pignataro - Secret_Doom -- secret_doom@hotmail.com www.batch.hpg.com.br

By the way, here's the asm unasselbled source code: 0000 CMP CX,+00 0003 JZ 001F 0005 MOV SI,0100 0008 CMP AX,0004 000B JZ 0016 000D MOV DI,00FF 0010 CMP BYTE PTR [SI],0A 0013 JNZ 0016 0015 INC AX 0016 MOVSB 0017 LOOP 0008 0019 MOV CX,DI 001B SUB CX,0100 -- Leonardo Pignataro - Secret_Doom -- secret_doom@hotmail.com www.batch.hpg.com.br