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Passing a pause w/ start command
Name: Robin Siebler Date: September 26, 2003 at 11:29:16 Pacific OS: Win2k CPU/Ram: NA
Comment:
I have the below batch file, which runs a bunch of batch files one at a time in a separate window. However, by default, the window remains open at the end and I have to close it. I tried using start /c, but that closes the window as soon as the batch file finishes, which does not let me see the contents of the window. I would like to insert a pause after the batch file runs. I tried 'start /c %%i & pause', but that didn't work. I tried enclosing it in parenthesis and that didn't work either. Can anyone tell me the *right* way to do this?
Name: JackG Date: September 26, 2003 at 14:43:57 Pacific
Reply:
Try a two step approach. For each t*.bat, Start a CMD that just runs X.BAT %%i where X.BAT has a CALL %1 %2 %3 followed by a Pause and if necessary an EXIT.
This way, each window is running a batch file sequence with a Pause statement at the end and an exit to close the window.
You can then change the function of X.bat by editing it when necessary.
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Response Number 2
Name: robinsiebler Date: September 29, 2003 at 11:18:08 Pacific
Reply:
Is there anyway to do this in 1 batch file?
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Response Number 3
Name: Robin Siebler Date: September 29, 2003 at 15:00:59 Pacific
Reply:
I couldn't figure out how to do it in 1 file, so I wrote the batch file to create a temp batch file containing the call, pause and exit statements and then delete the temp file at the end.
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Response Number 4
Name: Miskva Date: October 3, 2003 at 02:30:32 Pacific
Reply:
Maybe you need to have the "pause" command at the end of each of the batfiles you are running .. and not in the main loop ..;
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