within a batch file, Is there a way to set a variable to be equal to the system date minus seven days?

i wrote a small calculater for dos, you can use it in a batchfile, if you firm with batchfile programming, you can use it for that problem, if not -> mail me download SCALC.COM under downloads from http://plop.at

Bitbyte's SCALC.COM is a great program, useful on batch files under DOS/Win9x. However, in NT systems such as Win 2000, the command prompt itself can do all it does (and much more). Here's a sample: set DAY=30 set /A DAY -= 7 For more information about doing arithmetic operations with the SET command, type "SET/?" on the command prompt. However, that still doesn't solve all your problem, that's actually the easy part. You gotta get the date, subtract 7 from the day, and do the necessary calculations if the new resulting day is less than 1. Such calculations aren't that simple, you gotta calculate the new month, calculate the new date based on that, sometimes check if the year has a 29-day-february, etc. The following batch file will do it: @echo off for /F "tokens=2-4 delims=/- " %%A in ('date/T') do (     set M=%%A     set D=%%B     set Y=%%C ) if "%D:~0,1%"=="0" set D=%D:~1% if "%M:~0,1%"=="0" set M=%M:~1% :: Subtract the desired number of days set /A D -= 7 :arrange if %D% GTR 0 goto dateOK set /A M -= 1 set /A BX = %Y% %% 4 if %M% GTR 0 goto keepyear set /A Y -= 1 set /A M += 12 :keepyear for %%? in (1 3 5 7 8 10 12) do if %M% == %%? set /A D += 31 for %%? in (4 6 9 11) do if %M% == %%? set /A D += 30 if %M% == 2 (     if %BX% EQU 0 set /A D += 29     if %BX% NEQ 0 set /A D += 28 ) goto arrange :dateOK if "%D:~1%"=="" set D=0%D% if "%M:~1%"=="" set M=0%M% The variables are M D and Y, with month and date with 2 digits and year with 4. -- Leonardo Pignataro - Secret_Doom -- secret_doom@hotmail.com www.batch.hpg.com.br __________________________________________________________________

Nice site bitbyte. Also try: MrHall

to SkipCox thanks, i looked at yours, a lot of interesting calculation programs