length of a string in a batch file

This will do it: :: Send the length of the variable %MyVar% :: to the variable %length% set #=%MyVar% set length=0 :loop if defined # (set #=%#:~1%&set /A length += 1&goto loop) echo MyVar is %length% characters long! -- Leonardo Pignataro - Secret_Doom -- secret_doom@hotmail.com www.batch.hpg.com.br ____________________________________________________________

excellent! just what I was looking for. Thanks.

I'm getting a syntax error when I try to use this code. Any thoughts as to why this might be happening? One thing I notice is that the command interpreter removes the %#:~1% bit. Is this by design? Thank you!