hello... I try to find some data with a batch in a list of 350 pages like this: directory of O:\directory\ 13.09.01 21:18 7.846.390 1.TIF 13.09.03 21:22 1.647.616 2.TIF o:\dir\ 13.09.01 21:15 18.296.710 4 Datei(en) 30.584.712 Bytes Anzahl der angezeigten Dateien: 331 Datei(en) 3.123.111 Bytes 4.543.225.856 Bytes free I need the second last line and I need from some dates the full line; for example all of year 01. I tried something like this in different versions: FOR /f "delims=" %%a in ('find "03" c:\3_3\speicherTif.txt') do echo %%a But I doesnīt really work. thanks for any help uli

PLease, explain better your search criteria: - what do you mean with "second last line"? - what are the lines you like to retrieve with full data ? Sorry, but your post left me confusing.

with second last line I mean the line who shows how many files and how many bytes the files need when typing the dir command: files :331 Datei(en) 3.123.111 Bytes From this lines 13.09.01 21:18 7.846.390 1.TIF 13.09.03 21:22 1.647.616 2.TIF I want to search for example all of year 2001. The reason is that we donīt have enough disk space so I want to find files wich are not used for longer time and burn it on CD and delete it from the file server. With the DIR command I can just sort in every directory and have to check the list manually. The line that shows me how many bytes the files use, I need for statistic. Sorry about my english uli

Hi uli, I am back and now I understand what you want to accomplish. The batch you find below should do the job, based upon your directives and lines sample. I tell you however the work could be fully automated and the reports better edited. I tested the script using your sample, but if anytging goes wrong or you need more support post again. To run type XScr FileName Year File_Out where FileName is your 350 pages list, year the Year and File-Out the file you want to hold the report (it may be CON or PRN i.e the screen and printer) I hope this helps. Good work @Echo Off :: XSCR.BAT Syntax: XScr FileName Year File_Out Echo. If %1.==. (Echo File missing & GoTo :EOF) If not exist %1 (Echo File "%~f1" not found & GoTo :EOF) If %2.==. (Echo Year missing & GoTo :EOF) If %3.==. (Echo Output missing & GoTo :EOF) Echo Screning "%~f1" for %2 - Output to "%~f3" Echo Screning "%~f1" for %2 - Output to "%~f3" > %3 Echo. >> %3 For /F "tokens=1-3* delims=. " %%A in (%1) Do ( If "%%C"=="%2" Echo %%A.%%B.%%C %%D >> %3 If "%%B"=="Datei(en)" Echo %%A %%B %%C.%%D >> %3) Echo Processing completed

Hi Ivo, thanks a lot. It works great. Just If "%%B"=="Datei(en)" Echo %%A %%B %%C.%%D >> %3 doesnīt work. It seems to be the same problem I had with with For.... "Datei (en)" is at the end of each directory listed. (There are many in the list) I just need the last line with "Datei(en)" in the list. (thats what I meant with second last in the list. ;-) ) I just know how to ignore the first x lines if I know how many lines they are. Is there a possibility to search the last line of "Datei (en)" ? greetings uli

Hi uli, To get only the last Datei line substitute in the script the lines starting with If "%%B"=="Datei(en)" Echo %%A %%B %%C.%%D >> %3) with the following If "%%B"=="Datei(en)" Set Datei=%%A %%B %%C.%%D) Echo. >> %3 Echo %Datei% >> %3 Echo. Echo Processing completed That catches only the last line of your interest.

Hi Ivo, it works perfect! thank you very much for help. uli