Hi.... I need some help with a batch to extract only part of a text string in a file..eg: Myfile.txt has lines consisting of "this is a text line" I need to know how to remove "this" and output "is a text line" to another file? the first word is the only part not needed i should mention each of the first word in each line ends with ">" without a space eg: "string>" Any help would be appreciated :) thanks in advance.

Maybe this helps: FOR /f "skip=2 delims= " %%a in ('find "is a text line" Myfile.txt') do >%%a skip=2 means not to seek in the first two lines (not necessary) delims=" is what you need. After= you give the last sign before the words you are seeking and the last sign. like "delims=x " or whatever. beginning and empty at the end of the word your seeking for). uli

Hi Uli.. This works but results in giving me the first word in the string...the part i dont need eg: "this> is a string" resulting in an output of "this>" ( using > as the delims) Also i do not know what the strings consist of, the only constant is ">" Am i making a mistake somewhere? i tried this.... FOR /f "skip=2 delims=>" %%a in ('find/v "0.0.0.0" Myfile.txt') do echo>%%a I can still use this elsewhere though or something along those lines thanks for your help dual

Hi dual, if I understand right I know the mistake. "delims=>" takes > as last sign. "delims=>-" takes > as first sign and - as last sign. (for example) So you need a start and a end sign. This should work. uli

Hi again Uli... Thanks for you help and time :) I managed to solve it with a slight difference..here is my solution: FOR /F "tokens=2,3* skip=2 delims= " %%i in ('find ">" Myfile.txt') do echo %%i %%j %%k>>line.txt Myfile.txt contains : this> is a line this> is another line this> is yet another line line.txt contains : is a line is another line is yet another line Your first post gave me the insight :) thanks again ! dual