Hi, how can I get all the DOS command line arguments in a single variable? If I were pass the args as: temp.bat a b c d e f, I want the assign all the args as a sentence in a single variable. e.g var1="a b c d e f"

set var=%1 %2 %3 %4 %5 %6 ===================================== If at first you don't succeed, you're about average. M2

I am sorry, I did not make it clear earlier that the number of arguments may not be the same every time. It could be 6 or 5 or 4. Is there a common variable that holds all the args similar to $? in Unix.

I don't think so, but this: set var=%1 %2 %3 %4 %5 %6 will work if there is no %5 %6 etc. ===================================== If at first you don't succeed, you're about average. M2

Here you are in the real plain DOS Forum, i.e. the legacy MS (and its clones) operating system. Under that environment (up to Windows ME) you have to code set var= :LOOP if "%1"=="" goto :DONE set var=%var% %1 shift goto :LOOP :DONE echo. VAR=%var% However under NT kernel systems as Windows 2K/XP/Vista where the command interpreter is cmd.exe instead of command.com you can code set var=%* to catch the whole command tail by one shot.

IVO, this was exactly what I was looking for. Thank you very much.

Try using %* That represents all command line args except %0