I'm trying to write a DOS batch file that will determine which files are in a directory on a remote unix box and then write a ftp script go 'get' each of the files. So far I have writen a script that carries out 'ls' on the remote unix box and output the result to a file. The script then uses 'find' to filter out the unwanted filenames. The next part of the script writes a ftp script and outputs the ftp comand 'get' for each of the filenames using a 'for' loop (ie. for /F %%f in (filename) do echo get %%f >> ftpscript). The batch file then executes the ftp script, however when trying to carry out get the error "Cannot open local file X". The whole script is as below, @echo off echo open host > c:\ftp_ls.scr echo user>> c:\ftp_ls.scr echo password>> c:\ftp_ls.scr echo ascii >> c:\ftp_ls.scr echo ls >> c:\ftp_ls.scr echo close >> c:\ftp_ls.scr echo quit >> c:\ftp_ls.scr ftp -s:c:\ftp_ls.scr > c:\files.lis echo open host > c:\getfiles.scr echo user>> c:\sas\dyp\getfiles.scr echo password>> c:\getfiles.scr echo ascii>> c:\getfiles.scr for /F "skip=2" %%f in (c:\sasfiles.lis) do echo get %%f>> c:\getfiles.scr echo close>> c:\getfiles.scr echo quit>> c:\getfiles.scr cd temp ftp -s:c:\getfiles.scr cd ..