Hi every body I need to count the number of line in a file. My file is like this: |tetrte|ezrzer|||||erez| |tetrte|ezrzer|||||erez| |tetrte|ezrzer|||||erez| I found something: find /C "|" filename I am a newbie in Dos so don't manage to get the result number in a single variable. Set toto = find /C "|" filename... Thx for help, Smilaou

I see that i can redirect the count in a file but on the same line i need to write a message: echo fin 'The count' > filename this don't work :(

Hi smilaou... I think this is what you need... try it! echo e100'set %%1='> %temp%.\temp.bat for %%? in (rcx 7 w q) do echo %%?>> %temp%.\temp.bat type %temp%.\temp.bat |DEBUG %temp%.\temp.bat > nul rem Find the count in (somefile.ext) find /c "|" < somefile.ext >> %temp%.\temp.bat rem: sets result of FIND to the variable "number" call %temp%.\temp.bat number del %temp%.\temp.bat echo Finished The count is %number% > result.ext set number= :eof result.ext would have one line as this " Finished The count is 5" for example dual

A rather simpler one-liner can be found here: http://discussions.virtualdr.com/showthread.php?s=&threadid=146504

Thats a good one Rambler However it's not clear if the file would contain other unknown characters not specified in /V if so the count would be inacurate, also no %variable% is set and no echo of the desired line to a file Just a thought? im learning here too Dual