I'm am wanting to know if anyone knows how to write a batch file that will check the pc to see what day it is(ex. Mon.Tues.Wed, etc.)and if it is that day then call another batch to run, but if it is not that specific day then exit. Also on the specified day once the batch file has ran the secondary batch once I don't want it to run that batch again. If anyone can help I would appreciate it.

Thomas, try something along the lines of this. ECHO. | DATE | FIND "Fri" > nul IF NOT ERRORLEVEL 1 CALL BATCH.BAT If you want to delete the batch file that is called on the day, you will need to test in the calling batch file. This is because you can not delete an Open, running, file. So you would have lines like the ones above except you would DEL BATCH.BAT insted of callingit. Where as on the other hand if you want to delete the calling batch file you will have to do it from the called batch file. Same reason as above. If you have questions email me, drscriptt@yahoo.com, and I'll try to give you more info.

Oh, yah, DOS does not have a native way to schedule tasks in the background. You will have to turn to some 3rd party, non-MS-DOS, solution. I have used Task Scheduler with much success.

Oh, well... DOS hasn't NATIVE schedulers, that's why we are meant to make them =D This should solve your problem: @echo off echo. |date |find /i "FRI" > nul if errorlevel=1 goto nottoday if exist c:\check.dat goto end call batch.bat rem > c:\check.dat goto end :nottoday if exist c:\check.dat del c:\check.dat :end That will create a temporary file c:\check.dat. Leave it alone (you can change it's location by the batch) Any further question, letme know! -- Secret_Doom -- secret_doom@hotmail.com secretdoom.hpg.com.br PS: There is a little chance that one day the batch doesn't call the second one. That will happen only if you boot once in friday, don't boot for the whole week and then do only boot in the next friday.